Hello lovely members of xG!
Let me start with a simple introduction of myself...
I go by the username 'Legacy' or 'Thydemented' on CS:GO, Minecraft, and Starcraft 2. I have been playing quite a bit of xG's Jailbreak recently, and during studies in the last few days after being a Warden for the first night (due to chaotic events and no other step-ups), I have thought of a perhaps fun way to thin out the numbers of Terrorists, but completely fairly (for the most part).
The idea for this game came from a chapter of a book I read a few months back, labeled World War Z. In this "game", all terrorists would be separated into groups of five, and make a small circle that is far enough separated from other groups as to not cause shenanigans. In each group the terrorists will pick TWO to die. (Game is titled 'Democracy' because it reflects the groups being able to VOTE who dies and who lives). Then, the warden will call ONE group at a time, and have the two chosen victims go to a secluded area against a wall, where they will be shot to death by the CT's. The cycle will repeat until all groups have had their victims killed.
On the very likely chance that a group does not have a full set of 5, it should be something like this ratio, (left number being total # of T's, right being how many die): [4:2];[3:1];[2;0];[1;0]. The reason that 2 has 0 deaths, is because they would obviously pick each other, and you can't really have an odd vote.
If a group fails to agree on their victims, all voted victims should die in that group. (Ex w/ persons 'A','B','C','D': A chooses B, B chooses A, C chooses A, D chooses C. In this example, A has 2 votes, B has 1 and C has 1. All three would die because two victims were not voted on.)
Hope you can change this around a bit to make it a fun game that leaves a psychological effect on the T's, seeing as how they have to choose which one of their brothers shall die. I think this is a bit more fun way than to just roulette the T's 3 times :D.
Hope to see you on Jailbreak!
~Legacy
