Foxxy 2 Posted July 24, 2012 4. A 3.00 x 104 kg box car is travelling in a positive x-direction at 4.00.m/s when it collides with and remains coupled (stuck) to a stationary 5.00 x 104 kg freight car. Calculate the velocity of the cars after the collision. (5 marks) 5. A 200 g steel ball moving in a negative x-direction at 100 cm/s strikes a 500 g steel ball moving in a negative x-direction at 60.0 cm/s. After the collision, the 500 g steel ball moves in a negative x-direction at 75.0 cm/s. What is the final velocity of the 200 g steel ball? (5 marks) 6. A 100 kg astronaut is standing on the outside surface of a 4.50 x 104 kg spacecraft. The astronaut jumps away from the spacecraft at 8.00 m/s. a. What happens to the spacecraft? (2 marks) b. What is the velocity of the spacecraft relative to the astronaut? Assume the direction of the astronaut is positive. (5 marks) Do my work niggas Share this post Link to post Share on other sites
Loki 0 Posted July 24, 2012 4. m1= 3 x 104 kg / m2= 5 x 104 kg / v= 4 m/s x1= 4ms/312 => x1= 0,13 x2= 4ms/520 => x2= 0,007 m1 + m2 - x1 / v => (3 x 104 ) + (5 x 104) - 0,13 / 4 m/s => (0,4875 x 104) m1 + m2 - x / v => (3 x 104 ) + (5 x 104) - 0,17 / 4 m/s => (0,6375 x 104) (0,4875 x 104) / (0,6375 x 104) = 0,765 = V (R/ The Velocity of the cars after collision equals 0,765) Hope that was of any help, too tired to try the other ones tbh. :D (I have no idea what I just fucking did ;D) Share this post Link to post Share on other sites
Mad_Scientist 8 Posted July 25, 2012 Throw a fucking watermelon at the wall and it explodes, the bits will also scatter. Share this post Link to post Share on other sites
Foxxy 2 Posted July 25, 2012 Well at least one of you isn't a mad science researcher Share this post Link to post Share on other sites
RainbowDashh 1 Posted July 25, 2012 Holy fuck im confused Share this post Link to post Share on other sites
VanillaGrape 0 Posted July 27, 2012 umm wtf i dont know what you just said.. Share this post Link to post Share on other sites